Physics, asked by deveshverma3710, 10 months ago

A bullet of mass 10g is fired with a rifle . The bullet takes 0.003s to move through its barrel and leaves with a velocityof 300 m/s . What is the force exerted on the bullet by the rifle?

Answers

Answered by Siddharthjatt
0

Answer:

F=1000N

Explanation:

t=0.003s , m=10g=10^-2 , v=300m/s

F=change in momentum / change in time

F= {(10^-2)(300)}/0.003

F=3/0.003

F=1000N

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