A can complete a work in 10 days b in 12 days and c in 15 days so in how many days they together complete the work?
Answers
Answered by
0
Answer:
8 days
Step-by-step explanation:
B+C)'s one day work = 110+115=1060=16
(B+C)'s two days work = 16×2=26=13
Remaining work = 1−13=23
Now 112 work can b done by A in one day.
23 work can be done by A in 23×12 = 8 days
Answered by
0
Answer:
37
Step-by-step explanation:
10 (A)
+
15(C)
+
12(B)
=37
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