Question

A bullet of mass 10g is fired with a velocity of 400 m/s strikes a wooden block of mass 2 kg

Answer 1

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Answer 2

Answer:

Explanation:

the question can be answered in any conservation meth . I use conservation of momentum

Mass of bullet = 10g = 10⁻² kg ; mass of block = 2kg

speed of bullet =  400m/s ; height raised = 0.1 m

for the block

mgh = 1/2mv²   ------- v =√(2gh) = 1.4 m/s

mv = m1v1 + m2v2

If v₂ is the final speed ,  v₂ =  (10⁻² x 400) - (2 x 1.4) / 10⁻2

                                            = (4 - 2.8) x 10²

                                             = 120 m/s

                               Hope you understand

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