a bullet of mass 10g is fired with a velocity of 400ms from a gun of mass 4kg.What is the recoil velocity of the gun
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Here no external force is acted (neglect air resistant) hence momentum of system(gun+bullet) is conserved
initial momentum = finial momentum
let the recoil velocity of gun = v
0.01*0 + 4*0 = 0.01*400 + 4*v
v = -1m/s
hence gun recoil with velocity 1m/s
initial momentum = finial momentum
let the recoil velocity of gun = v
0.01*0 + 4*0 = 0.01*400 + 4*v
v = -1m/s
hence gun recoil with velocity 1m/s
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the answer is the two velocity
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