Question

A bullet of mass 10g moving with a velocity of 400m/s gets embedded in a freely suspended wooden block of mass 900g .what is the velocity acquired by the wooden block.

Answer 1

Heya there

Let mass of bullet m1= 10g

Velocity v1=400m/s

And,

The mass of Wooden block m2 = 900g

Velocity v2 =?

m1v1 = m2v2

10 × 400 = 900 ×v2

4000 = 900 × v2

V2= 4000 /900

V2= 4.44m/s

Answer 2

Hey there

refer to attachment