Physics, asked by bobybora989, 9 months ago

A bullet of mass 10g moving with a velocity of 400m/s gets embedded in a freely suspended wooden block of mass 900g what is the common velocity of the bullet and block​

Answers

Answered by nademsrinivas62
0

Answer:

common velocity of the bullet and block 2500m/s

Answered by omanshkaushik
2

Answer:

linear momentum remain conserved.

hence

mv = MV

10/1000 × 400 = (10+900)/1000 × V

4 = 10V

V = (4/10)m/s

V = 0.4 m/s

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