A bullet of mass 10g moving with a velocity of 400m/s gets embedded in a freely suspended wooden block of mass 900g what is the common velocity of the bullet and block
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Answer:
common velocity of the bullet and block 2500m/s
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Answer:
linear momentum remain conserved.
hence
mv = MV
10/1000 × 400 = (10+900)/1000 × V
4 = 10V
V = (4/10)m/s
V = 0.4 m/s
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