A bullet of mass 10g moving wits a velocity of 400m/s get embedded in a freely suspended wooden block of mass 900g. What is the velocity acquired by the block?
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By using law of conservation of momentum
m₁u₁ = (m₁ + m₂)v
v = m₁u₁ / (m₁ + m₂)
= (10 × 10^-3 kg × 400 m/s) / [(10 + 900) × 10^-3 kg]
= 4.395 m/s
Velocity acquired by the wooden block is 4.395 m/s
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