A car is moving on a straight road with uniform acceleration. The speed of car varies with time as follows.

Draw the speed-time graph: by choosing a convenient scale. Calculate (i) the acceleration of a car. (ii) distance travelled by the car in 10 second.
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a=tantheta
tantheta=p/b
tantheta=v-u/t
a=30-5/50
a=0.5m/s^2
distance covered by body when time =10s
s=ut+1/2at^2
s=5×10+1/2×0.5×10^2
s=50+0.5×50
s=75m
tantheta=p/b
tantheta=v-u/t
a=30-5/50
a=0.5m/s^2
distance covered by body when time =10s
s=ut+1/2at^2
s=5×10+1/2×0.5×10^2
s=50+0.5×50
s=75m
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