Question

A bullet of mass 10g strikes a sand-bag at a speed of 10³m/s and gets embedded after travelling a distance of 5cm. Calculate:
i) The resistive force exerted by the sand on the bullet.
ii) The time taken by the bullet to come to rest.​

Answer 1

Answer:

F=10^5,T=10^-4

Explanation:

Given A bullet of 10 g strike the sand bag at a speed of 1000 m/s and gets embedded after travelling 5 cm. calculate

(a)Resistive force exerted by sand on bullet.

(b)Time taken by bullet to come to rest.

Given mass of bullet m = 10 g = 0.01 kg

Speed v = 1000 m/s

Distance s = 5 cm = 0.05 m

We know that F = ma  

and v^2 = u^2 – 2as  

or a = v^2 – u^2 / 2s

      Now F = m (v^2 – u^2 / 2s)

                 = 0.01 x (1000^2 – 0 / 2 x 0.05)

  Resistive force will be    F = 10^5 N

Now time taken to come to rest will be

S = (u + v / 2) t

So t = 2s / u + v

       = 2 x 0.05 / 1000

     t = 10 ^-4 secs

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