Question

a bullet of mass 10g traveling horizontally with a velocity of 150m/s collides with and sticks to a stationary wooden of mass 5kg . then both move off together same line. calculate the velocity with which they move​

Answer 1

Answer:

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Answer 2

Answer:

The Answer is 50N

Explanation:

Initial velocity of the bullet, u=150  ms  

−1

 

Final velocity of the bullet, v=0

Mass of the bullet, m=10 g=0.01 kg

Time taken by the bullet to come to rest, t=0.03 s

Let distance of penetration be s

v=u+at

0=150+a(0.03)  

⟹a=−5000 ms  

−2

    (- sign shows retardation)

v  

2

=u  

2

+2as

0=150  

2

+2×(−5000)×s

s=2.25 m

Magnitude of the force exerted by the wooden block, ∣F∣=m∣a∣

∣F∣=0.01×5000=50 N

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