Question

a bullet of mass 10g travels horizontally with a velocity of 100m/s. find out the energy of the bullet? ​

Answer 1

Answer:

50j

Explanation:

Ek - 1/2MV^2

1/2*1/100*10000

=50j

Answer 2

Answer:

Explanation:Using First Equation of Motion:

v=u + gt (g denotes acceleration due to gravity where g = 10m/s^2)

>100= 0+ 10t [initial velocity(u)=0

final velocity(v)=100m/s]

>100=10t

>t = 10 sec

Now,

By third equation of motion,

v^2 - u^2 =2gs [s is the displacement and g is the acceleration due to gravity]

On putting the values of v and u in the equation,

>(100)^2 - (0)^2= 2x10xs

>10000 - 0 = 20s

>10000=20s

>s = 500m

So,

Force = mass x acceleration

= m x g

=0.01 x10 [10 grams = 0.01 kg]

F =0.1 Newton or kg m/s^2

Now,

Energy = Force X Displacement

= F x s

=0.1 x 500

=50 Joule

Therefore, the energy of the bullet is 50 joule.

Hope it helps :)