A bullet of mass 10kg velocity=100m/s strikes a mud wall and rest after penetrating through 5m . What is the force of wall ?
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Answered by
7
u = 100m/s
v = 0m/s
using ,
v²-u² = 2as
-u² = 2as
-10000 = 10a
a = -1000m/s²
⇒F = ma
⇒F = 10×-1000
⇒F = -10000N
v = 0m/s
using ,
v²-u² = 2as
-u² = 2as
-10000 = 10a
a = -1000m/s²
⇒F = ma
⇒F = 10×-1000
⇒F = -10000N
Anurag19:
means
means , have u ever seen 10kg bullet :P
he he :P
thats only i want to say
hmm... i m just imagning it :P
if the bullet is of 10kg then , wt about the gun :P
it is little boy(atom bomb), the bullet of 10kg
:P , he he
do u got my invitation
yeahh...
Answered by
0
Answer: F=1000N
Explanation: Since, finally the bullet stops, therefore
loss in kinetic energy = initial kinetic energy.
Let F be the average resisting force ,m=10 g or 0.01kg ,S=5 cm =0.05m
So
2
mv
2
=FS⇒
2
0.01×100
2
=F×0.05
So F=1000N
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