show that 6n cannot end with the digit 0 for any natural number
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60
6 = 2 x 3
6n = (2 x 3) n
3 never ends with 0
therefore 6 never ends with 0
6n = (2 x 3) n
3 never ends with 0
therefore 6 never ends with 0
noddy1:
hey.. in this ques n is the power of 6
Answered by
29
6 is obtained by 2x3.
therefore it is a multiple of 3.
Multiples of 3 never end with 0.
Therefore 6n where n is natural cannot end with 0.
therefore it is a multiple of 3.
Multiples of 3 never end with 0.
Therefore 6n where n is natural cannot end with 0.
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