A bullet of mass 10x10 kg moving with a
speed of 20ms- hits an ice block (0°C) of 990g
kept at rest on a frictionless floor and gets
embedded in it. If ice takes 50% of K.E, the
amount of ice melted (in grams) approximately
is (5=4.2J/cal) (Latent heat of ice = 80cal/g)
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Answer:
answer is 4023m/s velocity
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