A bullet of mass 15 g has a speed of 400 m/s. What is its kinetic energy ? The bullet strikes a thick target and is brought to rest in 2 cm, calculate the average net force acting on the bullet. What happens to kinetic energy originally in the bullet?
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A bullet of mass 15 g has a speed of 400 m/s. What is its kinetic energy ?
Kinetic energy K.E. = 1/2mv²
= 1/2 * 15/1000 * (400)²
= 1200 J Ans.
The bullet strikes a thick target and is brought to rest in 2 cm, calculate the average net force acting on the bullet.
Work done = Change in K.E.
Final velocity = 0
∵ Change in KE = Kf - Ki = 1200 J
∴ F * d = 1200
(Here, F is the average force)
F = 1200 / 2*10^-2
= 6 * 10^4 N Ans.
What happens to kinetic energy originally in the bullet?
Ans.) The kinetic energy is converted to heat energy.
Kinetic energy K.E. = 1/2mv²
= 1/2 * 15/1000 * (400)²
= 1200 J Ans.
The bullet strikes a thick target and is brought to rest in 2 cm, calculate the average net force acting on the bullet.
Work done = Change in K.E.
Final velocity = 0
∵ Change in KE = Kf - Ki = 1200 J
∴ F * d = 1200
(Here, F is the average force)
F = 1200 / 2*10^-2
= 6 * 10^4 N Ans.
What happens to kinetic energy originally in the bullet?
Ans.) The kinetic energy is converted to heat energy.
Anonymous:
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Answered by
179
Hi Abhi !!
Mass = m = 15 g = 0.015 kg [ 1kg = 1000 g ]
Velocity = v = 400 m/s
K.E = 1/2 mv²
= 1/2 × 0.015 × 400 × 400 = 1200 Joules
Work done = K.E
W = 1200 J
W = F × s
s = 2 cm = 0.02 m
1200 = 0.02 F
F = 1200 / 0.02
F = 60000 N ==> Answer
The energy gets converted to Heat Energy .
Hope this helps you :)
Mass = m = 15 g = 0.015 kg [ 1kg = 1000 g ]
Velocity = v = 400 m/s
K.E = 1/2 mv²
= 1/2 × 0.015 × 400 × 400 = 1200 Joules
Work done = K.E
W = 1200 J
W = F × s
s = 2 cm = 0.02 m
1200 = 0.02 F
F = 1200 / 0.02
F = 60000 N ==> Answer
The energy gets converted to Heat Energy .
Hope this helps you :)
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