Question

A bullet of mass 15 gram leaves the barrel of gun with a velocity of 120 metre per second with a velocity of 1 metre per second find the mass of the gun​

Answer 1

Answer:

Explanation:

Mass of bullet=15 g(M1)

Both initial velocity is 0 so U1 and U2=0

velocity 1=120 metre per second(V1)

velocity2=-1 metre per second(V2)

according to conservation of momentum

M1V1+M2V2=M1U1+M2U2

So 15*120+M2*(-1)=0

OR3000-M2=0

OR M2=3000g=3kg

Answer 2

Answer:

M2 =1800

Explanation:

M1=15,V1=120m/s,U1=0

M2=X,V2=(-1)(because gun is recoiling)U2=0

M1*U1+M2*U2=M1*V1+M2*V2

15*0+M2*0=15*120+M2*(-1)

0=1800*(-1)+M2

0=(-1800)+M2

1800=M2