A bullet of mass 15g has a velocity of 400m/s. What is its kinetic energy if the bullet strikes a thick target and is brought to rest in 2cm.
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Answer:
KE=1200J
F=6×10^4N
Explanation:
okay i dont get the use if the last piece of info given. I guess u wanted to type resistive force by thick target but i will tell you both
KE of the bullet will be 1/2 ×mv^2
m=15g=0.015kg
: . KE= 1/2 × 0.015×400×400
this simplifies to
KE=1200J
For force
W=Fs
W=(KE)f-(KE)i
W=-1200J
-1200=F×0.02
F=6×10^4N
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