Question

A bullet of mass 15g is fired from rifle. The bullet take 0.005sec move through its barrel and leaves it with velocity of 400m/s.what is the force exerted by rifle on bullet​

Answer 1

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Tangential acceleration of body is given -

at = 5 m/s^2

Centripetal acceleration of body is -

ac = v^2 / r

ac = 20^2 / 80

ac = 5 m/s^2

Angle of resultant acceleration vector with radius,

tanθ1 = ac / at

tanθ1 = 5/5

tanθ1 = 1

θ1 = arctan(1)

θ1 = 45°

We know that velocity vector is perpendicular to radius at any instant of time.

θ2 = 90°

Hence, angle between acceleration and velocity is

θ = θ1 + θ2

θ = 45° + 90°

θ = 135°

Therefore, angle between acceleration and velocity of the body is 135°.

Answer 2

Answer:

135 dergree is the answer