Question

Calculate the equilibrium constant for the reaction 02<=> 20 at temperatures of 298 k and 6000 k

Answer 1

Calculate the equilibrium constant for the reaction O2⇋ 2O at temperatures of 298 K and 6000 K. Verify the result with Table A.11.

TABLE A.11

Logarithms to the Base e of the Equilibrium Constant K

For the reaction vA A + vB B ⇋ vCC + vDD, the equilibrium constant K is defined as

Temp K

H2⇋2H

O2⇋ 2O

N2⇋2N

2H2O ⇋2H2+ O2

2H2O⇋ H2+2OH

2CO2⇋2CO +O2

N2+O2⇋2NO

N2+2O2⇋2NO2

298

-164.003

-186.963

-367.528

-184.420

-212.075

-207.529

-69.868

-41.355

500

-92.830

-105.623

-213.405

-105.385

-120.331

-115.234

-40.449

-30.725

1000

-39.810

-45.146

-99.146

-46.321

-51.951

-47.052

-18.709

-23.039

1200

-30.878

-35.003

-80.025

-36.363

-40.467

-35.736

-15.082

-21.752

1400

-24.467

-27.741

-66.345

-29.222

-32.244

-27.679

-12.491

-20.826

1600

-19.638

-22.282

-56.069

-23.849

-26.067

-21.656

-10.547

-20.126

1800

-15.868

-18.028

-48.066

-19.658

-21.258

-16.987

-9.035

-19.577

2000

-12.841

-14.619

-41.655

-16.299

-17.406

-13.266

-7.825

-19.136

2200

-10.356

-11.826

-36.404

-13.546

-14.253

-10.232

-6.836

-18.773

2400

-8.280

-9.495

-32.023

-11.249

-11.625

-7.715

-6.012

-18.470

2600

-6.519

-7.520

-28.313

-9.303

-9.402

-5.594

-5.316

-18.214

2800

-5.005

-5.826

-25.129

-7.633

-7.496

-3.781

-4.720

-17.994

3000

-3.690

-4.356

-22.367

-6.184

-5.845

-2.217

-4.205

-17.805

3200

-2.538

-3.069

-19.947

-4.916

-4.401

-0.853

-3.755

-17.640

3400

-1.519

-1.932

-17.810

-3.795

-3.128

0.346

-3.359

-17.496

3600

-0.611

-0.922

-15.909

-2.799

-1.996

1.408

-3.008

-17.369

3800

0.201

-0.017

-14.205

-1.906

-0.984

2.355

-2.694