Question

a bullet of mass 2.5 gram moving with a speed of 100 metre per second pierces a bag full of sand keep adjacent to a wall the bullet is stop in the bag after 0.05 second find(1) the acceleration of the bullet(2) force exerted by the send bag on the bullet​

Answer 1

Answer:

Bullet stops - this means that the final velocity of bullet is 0. Here assuming that the deceleration is constant, we apply equations of motion.

u= 100m/s

a=?

t= 0.05s

v= 0

a= v-u/t = 0-100/0.05= -2000m/s^2

F = ma=2.5*10^-3*2*10^3 =-5N