A bullet of mass 20 g and with the velocity of 150ms-1 moving horizontally strikes a wooden material and comes to rest in 0.02s. calculate the magnitude of the force exerted by the wooden material on the bullet.
Answers
Answered by
13
acceleration= 150/0.02m/s^-2
a= 7500m/s^-2
F=m×a=20×7500=15,000,0
F=1.5×10^5 Newton
a= 7500m/s^-2
F=m×a=20×7500=15,000,0
F=1.5×10^5 Newton
ankitasinghallha:
please mark as brainliest
Answered by
17
Answer:
Explanation:V=u+at 0=150+a×0.02;0=150+0.02a -0.02a=150;a=-150/0.02 a=-7500m/s^2 Mass of bullet=20g=0.02kg Force=mass/acceleration
=0.02×-7500
=-150 Newton
Similar questions
Social Sciences,
7 months ago
Math,
7 months ago
Math,
1 year ago
Physics,
1 year ago
History,
1 year ago