Question

A bullet of mass 20 g is fired horizontally with a velocity of 15
m/s from a pistol of mass 2kg. What is the recoil velocity of the gun?

Answer 1

Answer:

m1=20×10-³kg

v1=15m/s

m2=2kg

m1v1=-m2v2

20×10-³×15= -2×v²

v²=-20×10-³×15/2

v²=15×10-²

Answer 2

Answer:

recoil velocity of the pistal will be -0.15 mtr/sec.

Explanation:

given :-

mass of the bullet = 20 g

mass of the pistol = 2 kg

velocity of the bullet = 15 mtr/sec

recoil velocity of the pistol= ???

So,we know that,

Recoil velocity

= [ -mass of the bullet × velocity of the bullet ] ÷ [mass of the gun]

•  = - 20×15/2×10³
•  = - 20×15/2×10³ 
•  =  -0.15 mtr/sec

I hope this may help you.

GOOD NIGHT