A bullet of mass 20 gram is horizontally fired with
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Answered by
5
mass1=0.02kg
u1=0m/s
v1=150m/s
mass2=2kg
u2=0m/s
v2=v.
∴by the law of conservation of momentum,
m1u1+m2u2=m1v1+m2v2
0.02*0+2*0=0.02*150+2*v
⇒0+0=3+2v
⇒3=2v
⇒3/2=v
⇒1.5=v
∴recoil velocity = 1.5 m/s
i hope that this will help u..................
Answered by
2
Answer:
mass1=0.02kg
u1=0m/s
v1=150m/s
mass2=2kg
u2=0m/s
v2=v.
∴by the law of conservation of momentum,
m1u1+m2u2=m1v1+m2v2
0.02*0+2*0=0.02*150+2*v
⇒0+0=3+2v
⇒3=2v
⇒3/2=v
⇒1.5=v
∴recoil velocity = 1.5 m/s
i hope that this will help u........
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