Question

A bullet of mass 20 gram is horizontally fired with a velocity of 150 M per second from a pistol of mass 2 kg what is the recoil velocity of the pistol

Answer 1

According to conservation of linear momentum
MV = mv
2000 V = 20×150
V 2000 = 3000
V = 3000/2000
V = 1.5 m/s

Answer 2

Mass of bullet, m1 = 20 g = 20 / 1000 = 1 / 50 kg
Mass of pistol, m2 = 2 kg
Velocity of bullet, v1 = 150 m/s
Recoil velocity of pistol = (-m1 × v1) / m2
= (-1/50 × 150) / 2
= -3 / 2
= -1.5 m/s


This is the required answer.......