Question

A bullet of mass 20 gram is horizontally fired with a velocity 150 metre per second from a pistol of mass 2kg what is the recoil velocity of the pistol

Answer 1

______✨ HEY MATE ✨_______

➡️Here is your SOLUTION ⤵️

Mass 1 = 0.02kg
U1 = Om/s
V1 = 150m/s
Mass 2 = 2 kg
U2 = Om/s
V2 = v.
Hence , by the law of conservation of momentum ,
m1u1+m2u2 = m1v1+m2v2
0.02*0+2*0 = 0.02*150+2*v
=> 0+0 = 3 + 2v
=> 3 = 2v
=> 3/2=v
=> 1.5= v
Hence , Recoil velocity = 1.5m/s.

✌️ I THINK IT HELPED YOU ✌️