A bullet of mass 20 gram strikes a sandbag at a speed of 10 metre per second and gets embedded after travelling 10 centimetre calculate the resistive force exerted by the sand on the bullet to come to rest.
Answers
Answer ---->
10 N
Explanation:
Given-----> Mass of bullet is 20grams and bullet strikes a sandbag at a speed of 10 m/sec and gets embedded after travelling 10 Cm
To find -----> Find the resistive force exerted by the sand on the bullet to come to rest
Solution-----> ATQ,
Bullet of mass = 20 gram
= 20 × 10⁻³ kg
Initial velocoity of bullet = 10 m / sec
Final velocity of bullet = 0
Distance travelled by bullet = 10 Cm
= 10 × 10⁻² m
Now by third equation of motion ,
2as = v² - u²
=> 2 a ( 10 × 10⁻² ) = ( 0 )² - ( 10 )²
=> 20 × 10⁻² a = - 100
=> a = - 100 / 20 × 10⁻²
=> a = - 100 × 10² / 20
=> a = - 5 × 10²
=> a = - 500 m / s²
Negative value of a shows that , it is retardition and sand applied resistance at bullet ,
Now we know that ,
Force = mass × acceleration
So,
Resistive force applied by sand on bullet
= mass of bullet × acceleration
= 20 × 10⁻³ × 500
= 10000 × 10⁻³
= 10 N
Answer:
10N
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