Question

a bullet of mass 20g fired is fired with a velocity of 150 m\s from pistol of mass 2 kg. what is the recoil velocity of the pistol​

Answer 1

Answer:

1.5 m/s

Explanation:

mass of bullet ; m1= 20g

velocity of bullet v1 = 150m/s

mass of the gun m2 = 2kg =2000g

velocity of the gun v2 = ?

According the law of conservation of momentum

m1v1 = m2v2

20x150 = 2000xv2

3000 =2000xv2

3000/2000 =v2

1.5 = v2

∴ The recoil velocity of the gun = 1.5m/s