A bullet of mass 20g is filed horizontally
with a velocity of 150m/s from a pistol of mass 2 kg. what is the
recoil velocity of the pistol?
Answers
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1
Answer:
1.5 m/s
Explanation:
According to law of conservation of linear momentum
m1 × v1 = m2 × v2
mass of pistol = 2 kg
mass of bullet = 0.02 kg
velocity of pistol = 150 m/ s
let recoil velocity of the pistol be v1
2 × v1 = 0.02 × 150
2× v1 = 3
v1 = 3/2
v1 = 1.5
Ans 1.5 m/ s
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