Question

a bullet of mass 20g is fired from a gun of mass 8kg with a velocity of 400m/s find out the recoil velocity of the gun


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Answer 1

Answer:

This is based on the conservation of momentum, according to this the momentum of bullet should be equals to momentum of gun.

Pbullet = Pgun

P= mv

Mass of bullet is 20 gm= 0.02 kg , velocity= 400m/sec

Mass of gun = 8kg, and let velocity is V

So, 0.02×400 = 8×V

So, V= 1 m/sec

This is the recoil velocity of gun

Answer 2

Answer:

-1 m/s

Explanation:

The system's initial momentum $P_{i} = 0$

$M_{bullet} = 20 g$  ( Mass of Bullet )

$M_{gun}=8kg$    ( Mass of Gun )

$V_{bullet} = 400 m/s$ (Velocity of Bullet )

The conservation of linear momentum has been used below,

$P_{f} =P_{i}$

$M_{gun} V + M_{bullet} V_{bullet} = 0$

$8V + 0.02 * 400 = 0$

$8V + 8=0$

$8V = -8$

$V =\frac{8}{-8}$

$V = - 1 m/s$