A bullet of mass 20g is found to pass two point 30m apart in a time interval of 4 second.Calculate the kinetic energy of the bullet if it move with constant speed
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KE=1/2mv^2
and v=s/t thus v=30/4=15/2
m(in kg)=20/1000kg
now K.E= (20/1000)×15/2×15/2
=225/250
=45/50
=9/10
=0.9J
and v=s/t thus v=30/4=15/2
m(in kg)=20/1000kg
now K.E= (20/1000)×15/2×15/2
=225/250
=45/50
=9/10
=0.9J
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