A bullet of mass 20g is horizontally fired with a velocity of 20m/s from a pistol of mass 2kg what is the recoil velocity of a pistol
Answers
Answered by
4
Acc. to Newtons 3rd law,
m1v1=m2v2.
v2=-m1v1/m2
v2=0.02×20/2
v2=0.2m/s.
mark BRAINLIEST PLEASE.
m1v1=m2v2.
v2=-m1v1/m2
v2=0.02×20/2
v2=0.2m/s.
mark BRAINLIEST PLEASE.
Similar questions