Question

A bullet of mass 20g is moving with a velocity of 400m/s it strikes the target and penetrates 10cm to it and comes to rest
Calculate :
i) The retarding force offered by the target
ii) If the thickness of the target is reduced to 6cm , calculate at what speed will the bullet emerge out of the target.
No Spam please​

Answer 1

Explanation:

Given:

mass=m=20g=20/1000=0.02kg 

Initial velcoity=u=150m/s

Final velocity=0m/s

s=10cm=0.1m

According to Work _ Kinetic Energy Theorm

k-K1=W-Fs

1/2mu²-0=Fs

F=mu²/2s

=0.02x(150)²/2x0.1

=2250N

∴The average force of resistance offered by the target is 2250N

hope it will be helpful to you

###sakshi

Answer 2

Explanation:

now msg on that id

plz

it's Mr.Jatt