Question

a bullet of mass 20g moving with a speed of 500m/s strickes a wooden block of mass 1 kg and gets embedded in it . the speed of black - bullet system will be ​

Answer 1

Mass of bullet = m =

1000

20

kg

Mass of system after collision = m

′

=

1000

20+980

kg

final velocity after collision = v'

a)

2

1

m

′

v

′2

=

2

1

kx

2

v' =

m

′

k

x

20+980

100×1000

10cms

−1

=100cms

−1

=1ms

−1

b)Using conservation of momentum,

mv=m'v'

1000

20

v=

1000

980+20

×1

v=50ms

−1

c) Kinetic energy lost due to collision =

2

1

m

′

v

′2

−

2

1

mv

2

=-24.5 J

Answer 2

Explanation:

$m1v1 = m2v2$

$20 \times 500 = 1 \times v$

$1000 = v$

$v = {10}^{3} m {s}^{ - 1}$

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