A bullet of mass 20g moving with a speed of 75ms-1 hits a fixed wooden plank and comes to rest after penetrating a distance of 5cm.What is the average resistive force exerted by the wooden plank on the bullet?
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m=20 g
u=75 m/s
v=0
x=5 cm=5/100 m
v²=u²+2as
0=75²+2*a*0.05
5625+0.1 a=0
a= -5625/0.1= -56025
f=ma= 0.02*-56025=-1120.5
u=75 m/s
v=0
x=5 cm=5/100 m
v²=u²+2as
0=75²+2*a*0.05
5625+0.1 a=0
a= -5625/0.1= -56025
f=ma= 0.02*-56025=-1120.5
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