A bullet of mass 20g moving with a velocity of 300kg on to the bank, with a horizontal velocity of 3m/s. With what velocity does the boat begin to move backward?
Ans-0.5m/s
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Solution:
V = mv/M.
m ---> Mass of the girl.
M ---> Mass of the boat.
v ---> Final velocity of the girl.
V ---> Final velocity of the boat.
V = 50*3/300 = 0.5 m/s.
V = mv/M.
m ---> Mass of the girl.
M ---> Mass of the boat.
v ---> Final velocity of the girl.
V ---> Final velocity of the boat.
V = 50*3/300 = 0.5 m/s.
diyaekka052p0r3il:
how did 50 came ??
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