a bullet of mass 20g strikes a target with a velocity 100m/s and comes to rest 50percent kinetic energy of the bullet
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is the answer 50 joule?
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Dear Student,
◆ Complete question -
Q. A bullet of mass 20g strikes a target with a velocity 100m/s and comes to rest. 50% kinetic energy of the bullet raises its temperature by 25 C. Calculate specific heat of material of bullet.
● Answer -
s = 100 J/K
● Explanation -
Given that 50% kinetic energy of the bullet raises its temperature by 25 C.
50/100 × (1/2 mv^2) = m × s × T
1/4 v^2 = s × T
s = v^2 / (4 × T)
s = 100^2 / (4 × 25)
s = 100 J/K
Hence, specific heat of material of the bullet is 100 J/K.
Thanks dear. Hope this helps you...
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