Physics, asked by anany7792, 1 year ago

A bullet of mass 25 gram moving with a velocity of 150 M per second strikes a target and is brought to rest in one 1/100of a second the impulse is???

Answers

Answered by singhpiyush174pdla6s
1
impulse= change in momentum
= 0.025kg×(0-150) m/s
= 3.75 kg m/s.

thanks for asking.
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