A bullet of mass 25g strikes a wooden target with a velocity of
and emerges with a velocity of
Find the loss in energy during the process of penetration.
Answers
Answered by
14
Hi there ,
Initial K.E = 1/2 mv^2
= 1/2 × 25/1000 ×100×100
= 125 J
Final K.E = 1/2 × 25/1000 × 20 × 20 =5J
Therefore, loss of K.E , during Penetration= (125 -5)
Answer is = 120 J
Initial K.E = 1/2 mv^2
= 1/2 × 25/1000 ×100×100
= 125 J
Final K.E = 1/2 × 25/1000 × 20 × 20 =5J
Therefore, loss of K.E , during Penetration= (125 -5)
Answer is = 120 J
thawayitsshine:
wow ! Thanks
Answered by
6
_______________________________
_________________________________
Given:- Mass of bullet (m) = 25g = 25/1000 kg
Initial velocity of bullet (u)= 100m/s
Final velocity of bullet (v) = 20m/s
Loss in energy = ?
________________________________________
Solution:-
Initial Kinetic energy = (1/2)mu²
initial K. E. = (1/2) × (25/1000) × 100 × 100
= 250/2 = 125 Joule
Final kinetic energy = (1/2)mv²
Final K. E. = (1/2) × (25/1000) × 20 × 20
= 5 Joules
Loss in kinetic energy = Initial energy - final energy
=> 125 - 5
= 120 Joules
______________________________________
Hope it helps u out ( ^∇^)
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