Question

please solve by quadratic formula​

Answer 1

4x^2 - 4 a^2 x + ( a^4 - b^4)= 0

For ax^2 + bx + c= 0

x= - b+- √b^2 - 4ac))/ 2a

Here a= 4

b= -4a^2

c= a^4 - b^4

So x= -(-4a^2) +- √(4a^2)^2 - 4(4)(a^4 - b^4))))/ 2(4)

x= 4 a^2 +- √( 16 a^4 - 16 a^4 + 16 b^4)))/ 8

= 4 a^2 +- √16 b^4)) / 8

= 4 a^2 +- 4 b^2))/ 8

= 4( a^2 +- b^2)/ 8

= a^2 +- b^2)/ 2

So

x= a^2 + b^2)/ 2, a^2 - b^2)/ 2

Answer 2

Heya!!!

USING QUADRATIC FORMULA.

x = - b +– √ ( b² - 4ac ) /2a

b = -4a² a = 4 And c =( a⁴ - b⁴ )
_______________________________

x =

4a² +– √ ( 16a⁴ - 4 ( 4 ) ( a⁴ - b⁴ )
____________________
2 ( 4 )

=>

x =

4a² +– √ ( 16a⁴ - 16a⁴ + 16b⁴ )
____________________
2 ( 4 )

=>

x =

4a² +– √ (16b⁴ )
___________
8

=>

x = 4a² +– 4b² /8

=>

x = (4a² + 4b²) / 8 = ( a² + b² ) /2

OR

x = (4a² - 4b²) / 8 = ( a² - b² ) /2