Question

A bullet of mass 30g is horizontally fired with a velocity of 180m/s from a pistol of mass 2kg. what is the recoil velocity of the pistol?​

Answer 1

Answer:

Explanation:

Initial momentum of the system is 0 as it is at rest.

After firing-

                                   MV=mv

⟹V=  mv/V

​       =  0.03×180 / 2

​

⟹V= 2.7 m/s

MARK ME BRAINIEST