Question

A chord subtends an angle of 90°at the centre of a circle whose chord is 20 cm. Compute the area of the corresponding major segment of the circle.​

Answer 1

Answer:

Area of circle=πr²

=πr²

=314/100*20*20

=1256 cm

area of minor segment =theta/360*πr²-1/2*r²sin theta

=90*314*20*20/360*100 -1/2*20²()

=314-00

114cm²

area of major segment=area of circle -area of minor segment

=1256-114

=1142 cm²

Step-by-step explanation:

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