A bullet of mass 40g moving with speed90m/s enters a heavy wooden block and stopped after a distance 60cm.the average resistive force exerted by block on bullet
Answers
Answered by
5
Retardation of bullet is
a = u^2 / (2S)
= 90^2 / (2 × 60 × 10^-2)
= 6750 m/s^2
F = ma
= 40 × 10^-3 × 6750
= 270 N
The resistive force exerted by block on bullet is 270 N
a = u^2 / (2S)
= 90^2 / (2 × 60 × 10^-2)
= 6750 m/s^2
F = ma
= 40 × 10^-3 × 6750
= 270 N
The resistive force exerted by block on bullet is 270 N
Similar questions