Question

A bullet of mass 4g when fired with a velocity of 50m/s can enter a wall up to a depth of 10cm how much will be the average resistances offered by the walls

Answer 1

Given: Mass of Bullet = 0.004 kg
Initial Velocity (u) = 50 m/s
Final velocity = 0m/s
Penetration (s)= 0.1 m
v² - u² = 2as
⇒a = [0 - 2500]/(2)(0.1) = -1250m/s²
F = ma
⇒F = - 0.004 x 1250 = - 100N
The Force Exterted By Bullet on The wall is -100 N SO Acc to Newtons Third's Law The Force Exerted by wall on Bullet is +100N

Answer 2

Answer:

Given: Mass of Bullet = 0.004 kg

Initial Velocity (u) = 50 m/s

Final velocity = 0m/s

Penetration (s)= 0.1 m

v² - u² = 2as

⇒a = [0 - 2500]/(2)(0.1) = -1250m/s²

F = ma

⇒F = - 0.004 x 1250 = - 100N

The Force Exterted By Bullet on The wall is -100 N SO Acc to Newtons Third's Law The Force Exerted by wall on Bullet is +100N