Question

a bullet of mass 5 grams moving with velocity 100 m per second. penetrates the
wooden block up to 6 CM then average force imposed by the bullet on the block is

Answer 1

☺️☺️☺️
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Given,
Mass of the bullet $m = 5\: gms = 0.005\: kg$
Initial velocity of the bullet $u= 100\: m/s$
Final Velocity of the bullet will be zero.

Bullet penetrated the wooden Blocks up to 6 cm after hitting
$s = 6\: cm = 0.06\: cm$

--- $\underline{\textbf{Step-1}}$ :

Find the Acceleration possessed by the bullet

Using the formula,
$v^{2}-u^{2} = 2as$

$\implies 0-(100)^{2} = 2×a×0.06$

$\implies - (100)^{2} = 0.12a$

$\implies a = - \frac{10000}{0.12}$

$\implies a = - 83333.3\: m/s$

Here,
The sign -ve just indicates that the bullet is slowing down as it strikes the wooden block.
(In other words, it is the Negative Acceleration of the bullet)

--- $\underline{\textbf{Step-2}}$ :
Find the Average Force imposed on the wooden Block

Using the Formula,
$F = m \times a$

$\implies F = 0.05 \times 83333.3$
$\implies F = 416.67\: kg-m/s$

Therefore, the average force imposed on the wooden block is 416.7 N

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