A bullet of mass 50 gram is fired from a gun of mass 5 kg with an initial velocity of 40 metres per second what is the recoil velocity of the gun
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Given the mass of the gun, M = 10 kg, mass of the bullet, m = 0.05 kg Speed of the bullet, v = 500 m/s. Let the velocity of recoil of the gun = V Using conservation of momentum, we get Momentum after = momentum before MV – mv = 0 (as initial momentum was zero) or, MV = mv or, 10*V = 500*0.05 or, V = 25/10 = 2.5 m/s
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