the vont hoff factor for a 0.1M Al2(SO4)3 solution is 4.20.the degree of disssociation is?
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vont hoff factor i = 1-a+na where a = degree of dissociation and n = no. of compounds formed after dissociation.
4.2 = 1-a+2a
a= 3.2.
4.2 = 1-a+2a
a= 3.2.
mirza72:
sir i think it is 1 + 4a = 4.20... which implies 4a = 3.2 . which further implies a =0 .8 = 80%
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