Question

A bullet of mass 50g is horizontally fired from a pistol of mass 4 kg calculate the recoil velocity of the pistol if the velocity of the bullet is 35 m/s

Answer 1

Answer:

0.4375/s

Explanation:

given

m1=50g=0.05kg

m2=4kg

u=35m/s

we know that

.

v=0.05/4×35=0.4375m/s

Answer 2

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Accordin to newton's 2nd law,

m1v1=m2v2

Therefore

0.05×35=4×v (where v is recoil velocity of gun)

v= (0.05×35)/4

v= 0.435 kgm/s