Question

A bullet of mass 50g moving with a velocity of 100m/s strikes a wooden block of

mass 10 kg initially at rest. The bullet remains embedded in the block. Find the

velocity of system after the collision.​

Answer 1

Answer:

0.4975 m/s

Explanation:

Using conservation of momentum,

m*v1 + M*v2 = (m+M)*v

100 * 0.050 + 0 = (10 + 0.050)*v

v = 5/10.05 = 0.4975 m/s