Question

A bullet of mass 50g travelling with a speed of 15ms-1, penetrates into a bag of sand is uniformly brought to rest in 0.5s ... Find (a) The acceleration with which the bullet penetration units the bag of sand ? (b) The average force exerted by the sand ?​

Answer 1

m= 50g = 0.05kg

u=15m/s

t= 0.5 sec

v= 0 ( as bullet comes in rest)

from first law of motion

v=u+at

a=v-u/t

a=0-15/0.5 =-30m/s²

F = m×a = 0.05× 30

= -1.50 N