Question

a bullet of mass 50g with the speed of 500m/s it comes to rest in 0.01s mow finf the impulse and average force

Answer 1

here,
m=50g=0.05kg
u=500m/s
v=0
t=0.01s
by first equation of motion
v=u+at
0=500+a(0.01)
a=-500/0.01
= -50000 m/s²
impulse=F/t
= m.a/ t
=0.05×-50000 /0.01
= -250000

Answer 2

Here is answer..:) I hope you will understand it.......